554 prompts matching "Explain why a matrix with zero determinant has no inverse"
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Solving a double inequality
I am in SS 1. Quiz me with 5 short Additional Maths questions on solving a double inequali
Solving simultaneous linear equations by substitution
I am in SS 1. I'm going to explain solving a pair of simultaneous linear equations by the
Changing the subject when the variable appears twice
I am in SS 1. Teach me changing the subject of a formula where the required letter appears
Substituting values into an algebraic expression
I am in SS 1. Teach me substituting given numerical values into an algebraic expression co
Forming an algebraic expression from a word problem
I am in SS 1. Quiz me with 4 short Additional Maths questions on translating a short word
Solving a word problem using simultaneous equations
I am in SS 1. I'm going to explain a word problem that must be solved by setting up and so
Multi-part algebraic manipulation exam question
I am in SS 1. I attempted an Additional Maths question on a Cambridge/Additional Maths sty
Quiz me rapid-fire on expanding and factorising
I am in SS 1. I'm going to explain a rapid-fire quiz alternating between expanding a brack
Common sign errors in algebraic manipulation
Show me a fully worked Cambridge/Additional Maths style solution to a question on the most
Quiz: Writing a recurring decimal as a fraction to show it is rational
Act as my SS1 Further Mathematics tutor and quiz me on writing a recurring decimal as a fr
Final Revision: Approximating a surd to three decimal places
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Worked Example: What makes two surds equal
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Quiz: Reducing two surds to the same root in order to compare them
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WAEC Prep: Ordering a list of surds by size
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Worked Example: Adding two surds that simplify to the same root
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WAEC Prep: Squaring a single surd
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Spot My Mistake: Rationalising and then cancelling a common factor
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Final Revision: Expressing a rationalised answer in the form a root b over c
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WAEC Prep: Expressing the answer in the form a plus b root c
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Final Revision: Checking a conjugate answer by multiplying back
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